(2x-3)(3x^2+4x-5)=

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Solution for (2x-3)(3x^2+4x-5)= equation:


Simplifying
(2x + -3)(3x2 + 4x + -5) = 0

Reorder the terms:
(-3 + 2x)(3x2 + 4x + -5) = 0

Reorder the terms:
(-3 + 2x)(-5 + 4x + 3x2) = 0

Multiply (-3 + 2x) * (-5 + 4x + 3x2)
(-3(-5 + 4x + 3x2) + 2x * (-5 + 4x + 3x2)) = 0
((-5 * -3 + 4x * -3 + 3x2 * -3) + 2x * (-5 + 4x + 3x2)) = 0
((15 + -12x + -9x2) + 2x * (-5 + 4x + 3x2)) = 0
(15 + -12x + -9x2 + (-5 * 2x + 4x * 2x + 3x2 * 2x)) = 0
(15 + -12x + -9x2 + (-10x + 8x2 + 6x3)) = 0

Reorder the terms:
(15 + -12x + -10x + -9x2 + 8x2 + 6x3) = 0

Combine like terms: -12x + -10x = -22x
(15 + -22x + -9x2 + 8x2 + 6x3) = 0

Combine like terms: -9x2 + 8x2 = -1x2
(15 + -22x + -1x2 + 6x3) = 0

Solving
15 + -22x + -1x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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